What is the pH of a solution in which 25.0 mL of O.I M NaOH is added to 25 mL of O.08M HCI and final solution is diluted to 500 mL?

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answer is B.

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Detailed Solution

Milii-equivalents of HCl= 25 x 0.08 =2Milli-equivalents of Na OH = 2.5 remaining OH-=2.5-2500=10-3 [OH-] =10-3 so ∴ H+=10-11 or pH=11

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