First slide

PH of strong acids and strong bases

Question

What is the pH of a solution in which 25.0 mL of O.I M NaOH is added to 25 mL of O.08M HCI and final solution is diluted to 500 mL?

Moderate

A

3
B

11
C

12
D

13

Solution

Milii-equivalents of HCl= 25 x 0.08 =2
Milli-equivalents of Na OH = 2.5
$remaining [{OH}^{-}] = \frac{2.5 - 2}{500} = 10^{- 3} [{OH}^{-}] = 10^{- 3} so ∴ [H^{+}] = 10^{- 11} or pH = 11$

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