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What quantity of ammonium sulphate is necessary for the production of NH3 gas sufficient to neutralize a solution containing 292 g of HCl ? HCl=36.5; NH42SO4=132;NH3=17

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a

272 g

b

403 g

c

528 g

d

1056 g

answer is C.

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Detailed Solution

HCl=36.5; NH42SO4=132;NH3=17NH42SO4132 ≡ 2NH3 ≡ 2HCl236.5=73 gSince 1 mole of NH42SO4→2 NH3 which consumes 2moles ofHCl for neutralization 73 g HCl ≡ 132 g NH42SO4292 g HCl ≡ 528 g NH42SO4

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