What is the sum of radial and angular nodes in the following orbitals of H-atom?(I)   ψ2px         (II)   ψ2s     (III) ψ3dx      (IV) ψ3dx2-y2

Radial nodes = n – l – 1⇒ (I) n = 2,  l= 1, radial node = 2 – 1 – 1 = 0Angular node = 1 (YZ plane)(II) n = 2, l = 0, Radial node = 2 – 0 – 1 = 1Angular node = 0(III) n = 3, l = 2, Radial node = 3 – 2 – 1 = 0, andAngular node = 2 (XY and YZ planes)(IV) n = 3,  l= 2, Radial node = 0, andAngular nodes = 2Total = I + II + III + IV = 1 + 1 + 2 + 2 = 6