To what temperature must a neon gas sample be heated to double the pressure, if the initial volume of the gas at 75°C  is decreased by 15%?

Let          P1=P,V1=V  and              t1=75+273=348K.Thus, P2=2P,V2=(100−15)V100=85V100 and                         T2=?                     [∵   initial volume is decreased by 15%] Using gas equation, we have :  P1V1T1=P2V2T2T2=P2V2T1P1V1=2P×85V100×348KP×Vor   T2=591.6K=591.6−273=318.6∘C≃319∘CSo, the correct answer is  (a).