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Q.

At what temperature will the rate of diffusion of N2 be 1.6 times the rate of diffusion of SO2 at 27°C?

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a

3360C

b

300K

c

500C

d

630C

answer is D.

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Detailed Solution

r∝TMrN2rSO2=TN2MSO2MN2TSO21.6=TN228×64300 TN2=1.6×1.6×28×30064=336K=630C
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