At what temperature will the total KE of 0.3 mol of He be the same as the total KE of 0.40 mol of Ar at 400 K

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533 K

400 K

346 K

300 K

answer is A.

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Detailed Solution

KE=32nRT nT=constant n1T1 =n2T2 0.3 x T = 0.4 x 400 T = 533.33 K

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