First slide

Gaseous state

Question

At what temperature, will the total KE of 0.30 mole of He be the same as the total KE of 0.40 mole Ar at 400 K?

Moderate

A

533 K
B

400 K
C

346 K
D

300 K

Solution

$KE of n moles = \frac{3}{2} nRT (KE)_{He} = (KE)_{Ar} \frac{3 \times 0 .3 \times R \times T}{2} = \frac{3 \times 0 .4 \times R \times 400}{2} T = 533 .3 K$

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