First slide

Gaseous state

Question

At what temperature will the totat KE of 0.3 mole of He be the same as the total KE of 0.40 mole of Ar at 400 K?

Moderate

A

533 K
B

400 K
C

346 K
D

300 K

Solution

$KE = \frac{3}{2} nRT KE \propto nT (independent of gas) (KE)_{Ar} = (KE)_{He} 0 .4 \times 400 = 0 .3 \times (T)_{He} (T)_{He} = \frac{1600}{3} = 533 K$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App