Q.

What is the vapour pressure of solution prepared by mixing 25.5 g of CHCl3 and 40 g of CH2Cl2 at 298 K?

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347.9 mmHg

300 mmHg

200 mmHg

147.9 mmHg

answer is A.

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Detailed Solution

Molar mass of CH2Cl2=12×1+1×2+35.5×2 =85gmol−1 Molar mass of CHCl3=12×1+1×1+35.5×3 =119.5gmol−1 Moles of CHCl3=25.5119.5=0.213mol Moles of CH2Cl2=40g85gmol−1=0.47mol Total number of moles =0.47+0.213=0.683mol xCH2Cl2=0.47mol0.683mol=0.688 xCHCl3=1.00−0.688=0.312Using equation, ptotal =p1∘+p2∘−p1∘x2 =200+(415−200)×0.688 =200+147.9 =347.9mmHg

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