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Q.

What volume in mL of CO2 at STP will evolve when 1 gram of CaCO3 (If CaCO3 is very pure sample ) reacts with excess of dilute HCl?

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answer is 224.

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Detailed Solution

CaCO3→CO2+CaO1×nCaCO3=1×nCO21×1100=1×V22400V=224 ml
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