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Q.

What volume of O2 measured at standard conditions will be formed by the action of 100 ml of 0.5 N KMnO4 on hydrogen peroixde in an acid solution ? The skeleton equation for the reaction is2KMnO4 + H2SO4 + 5H2O2 →  K2SO4 + MnSO4 + H2O + O2

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a

0.12 L

b

0.28 L

c

0.56 L

d

1.12 L

answer is B.

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Detailed Solution

Eq. of O2 = Eq. of KMnO4 ⇒  w8 = 0.1 × 0.5 ⇒ w = 0.4 g ∴   32 g of O2 = 22.4 L at STP ∴ 0.4 g of O2 = 22.432 × 0.4 = 0.28
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