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What weight of a metal having equivalent weight 9 will give 1.14 g of its chloride?

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answer is 0.23.

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Detailed Solution

Eq. wt. of metal chloride = Eq. wt. of metal+ Eq. wt. of chlorine∴ Eq. wt. of metal chloride =9+35.5=44.5For 44.5 g of metal chloride, wt. of metal needed = 9 gFor 1.14 g of metal chloride, wt. of metal needed=9×1.1444.5=0.23 g. Ans.
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What weight of a metal having equivalent weight 9 will give 1.14 g of its chloride?