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Q.

What will be the correct representation of quantum numbers for the last electron entered into Ce?

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a

n = 4  l = 3 m = -3 s = -12

b

n = 4 l = 3 m = 0 s = -12

c

n = 4 l  = 2 m = -3 s = +12

d

n = 4 l = 3 m = +2 s = -12

answer is .

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Detailed Solution

Ce (Z = 58) f-block element: Last electron enters in f-orbital and highest value of n = 6 but the last electron will enter 4f-orbitals filled would be [Xe] 6s24f15d1
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