Q.
What will be the value of ΔG0 for the process at 298 K if the equilibrium constant for the process is 9 × 1012
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
8.314 J K−1 mole−1 × 298K × log9 × 1012
b
−8.314 J K−1 mole−1 × 298 K × ln9 × 1012
c
−2.303 × 8.314 J K−1 mole−1 × 298 K × ln9 × 10-12
d
2.303 × 8.314 J K−1 mole−1 × 298 K × log9 × 10-12
answer is B.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
ΔG0 = − RTlnKc ΔG0=− 2.303 RT log Kc
Watch 3-min video & get full concept clarity