Q.

What will be the value of ΔG0  for the process at 298 K if the equilibrium constant for the process is 9  ×   1012

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a

8.314  J K−1   mole−1  ×   298K   ×   log9   ×   1012

b

−8.314  J K−1  mole−1   ×  298 K   ×  ln9   ×   1012

c

−2.303   ×  8.314  J K−1  mole−1  ×   298 K  ×  ln9   ×  10-12

d

2.303  ×  8.314  J K−1  mole−1 ×  298 K ×  log9  ×  10-12

answer is B.

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Detailed Solution

ΔG0 = −  RTlnKc ΔG0=− 2.303  RT  log  Kc
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What will be the value of ΔG0  for the process at 298 K if the equilibrium constant for the process is 9  ×   1012