Q.

What will be the value of ΔG0 for the process at 298 K if the equilibrium constant for the process is 9 × 1012

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8.314 J K−1 mole−1 × 298K × log9 × 1012

−8.314 J K−1 mole−1 × 298 K × ln9 × 1012

−2.303 × 8.314 J K−1 mole−1 × 298 K × ln9 × 10-12

2.303 × 8.314 J K−1 mole−1 × 298 K × log9 × 10-12

answer is B.

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Detailed Solution

ΔG0 = − RTlnKc ΔG0=− 2.303 RT log Kc

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