What will be the volume of CO2 at NTP obtained on heating 10 grams of (90% pure) limestone?
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a
22.4 litres
b
2.016 litres
c
2.24 litres
d
20.16 litres
answer is B.
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Detailed Solution
CaCO310 g → CaO + CO210g of90% pure CaCO3=90×10100=9gFrom equation ,100g of CaCO3→22.4 lit of CO2 9g of CaCO3 → ?volume of CO2 obtained at NTP =9×22.4100=2.016L