First slide

Faraday's Laws

Question

What will be the weight of silver deposited, if 96.5 A of current is passed into aqueous solution of AgNO₃ for 100 s?

Easy

A

1.08 g
B

10.8 g
C

108 g
D

1080 g

Solution

$Q = it = 96.5 \times 100 = 9650 C$
96500 C charge deposited weight of Ag = 108 g
9650 C deposited weight of Ag $= \frac{108 \times 9650}{96500} = 10.8 g$

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