Q.
When 1-alkyne is treated with Na + Liq. NH3 and product is reacted with methyl chloride, the end product of the reaction will be
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a
Lower alkyne having two carbons less than 1-alkyne
b
Lower alkyne having one carbons less than 1-alkyne
c
Higher alkyne having one carbon more than 1-alkyne
d
Higher alkyne having two carbons more than 1-alkyne
answer is C.
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