Q.

When 1-alkyne is treated with Na + Liq. NH3 and product is reacted with methyl chloride, the end product of the reaction will be

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a

Lower alkyne having two carbons less than 1-alkyne

b

Lower alkyne having one carbons less than 1-alkyne

c

Higher alkyne having one carbon more than 1-alkyne

d

Higher alkyne having two carbons more than 1-alkyne

answer is C.

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