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When is strongly heated with ammonia the product formed is
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By Expert Faculty of Sri Chaitanya
a
B2H6
b
B3N3H6
c
BN
d
H3N→BCl3
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Correct option is C
BCl3+6NH3→BNH23+3NH4Cl Boron amide2BNH23→ΔB2NH3Boron imide+3NH3B2NH3→Δ2BN+NH3 Boron Nitride
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