When BCl3is strongly heated with ammonia the product formed is
B2H6
B3N3H6
BN
H3N→BCl3
BCl3+6NH3→BNH23+3NH4Cl
Boron amide
2BNH23→ΔB2NH3Boron imide+3NH3
B2NH3→Δ2BN+NH3
Boron Nitride