Q.
When CH3CH2CHCI2 is treated with NaNH2 the product formed is
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a
CH3CH=CH2
b
CH3-C≡CH
c
d
answer is B.
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Detailed Solution
CH3CH2CHCl2 →−HClNaNH2 CH3CH=CHCl →−HClNaNH2 CH3C≡CH
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