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When ${Cl}_{2}$ gas is passed through hot and cone. solution of $KOH,$ following compound is formed

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KCl

KClO3

KClO2

KClO4

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detailed solution

Correct option is B

6KOH+3Cl2→5KCl+KClO3+3H2O.

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When Cl2 gas is passed through hot and cone. solution of KOH, following compound is formed

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When ${Cl}_{2}$ gas is passed through hot and cone. solution of $KOH,$ following compound is formed