Trends in Atomic Properties & Physical Properties

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Question

When ethylene is heated with 1.5 moles of oxygen the heat liberated is 702kJ. Enthalpy of combustion of ethylene is

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Solution

$C_{2} H_{4} (g) + 3 O_{2} (g) \overset{}{\to} 2 {CO}_{2} (g) + 2 H_{2} O (l); ΔH = ?$
This equation represents combustion of ethylene
1.5 moles of $O_{2}$ when reacts with ethene liberates 702kJ
3 moles of $O_{2}$ when reacts with ethene liberates _____
${ΔH}_{combustion} = 2 (- 702) = - 1404 kJ$

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Trends in Atomic Properties & Physical Properties

Unlock the full solution & master the concept.

When ethylene is heated with 1.5 moles of oxygen the heat liberated is 702kJ. Enthalpy of combustion of ethylene is

C2H4g+3O2g→ 2CO2g+2H2Ol;ΔH=?This equation represents combustion of ethylene1.5 moles of O2when reacts with ethene liberates 702kJ3 moles of O2when reacts with ethene liberates _____ΔHcombustion=2(−702)=−1404kJ

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