When 2g of a gas A is introduced into an evacuated flask kept at 25ºC, the pressure is found to be 1 atmosphere. If 3g of another gas is then added to the same flask, the total pressure becomes 1.5 atm. Assuming ideal behaviour, the ratio of their molecular weights MA : MB is
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a
3 : 1
b
1 : 3
c
2 : 3
d
3 : 2
answer is B.
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Detailed Solution
n α P V,T are constant nAPA=nBPB=wBMBxPB=wAMAxPA MAMB=2x0.53x1=13 (Since pressure of gas B (PB) = 1.5 - 1 = 0.5)