Q.
When 1 g of zinc was treated with dil. H2SO4,360cm3 of H2 gas at 15∘C and 758 torr. was liberated. When 1g zinc was added to copper nitrate solution 0.965 g of copper was displaced. Calculate the equivalent weight of zinc and copper (1L of H2 gas weighs 0.09 g).
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
answer is 31.75.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
(i) P1=758 torr; V1=360cm3T1=15+273=288K;P2=760 torr; V2=?,T2=273K.Using gas equation, we have : P1V1T1=P2V2T2;V2=P1V1T1×T2P2=758 torr. ×360cm3×273K288K×760 torr. or V2=340.4cm3.1000cm3(=1L) of H2 weighs =0.09g ∴340.4cm3 of H2 weighs =0.09×340.41000g=0.0306g. Eq. wt. of Zn=Wt. of Zn×1.008Wt. of H2 at NTP=1×1.0080.0306 =32.9 g (ii) wt. of Zn=1g , Wt. of Cu=0.965g Eq. wt. of Cu=Eq.wt. of Zn×wt. of Cuwt. of Zn =32.9×0.9651=31.75
Watch 3-min video & get full concept clarity