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Question

When a graph is plotted between $\mathrm{log}x/m\text{and}\mathrm{log}p$ it is straight line with an angle 45° and intercept 0.3010 on y - axis . If initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gm of adsorbent

Moderate

Solution

$\begin{array}{l}\mathrm{log}\frac{x}{M}=\mathrm{log}k+\frac{1}{n}\mathrm{log}P\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\\ \frac{1}{n}=\mathrm{tan}{45}^{\circ}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\phantom{\rule{1em}{0ex}}\mathrm{log}k=0.3010\\ n=1\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}k=2\\ \frac{x}{m}=2\times (0.3{)}^{1}\Rightarrow x=0.6\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\end{array}$

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The pressure of the gas decreases from 380 mm of Hg to 190 mm of Hg. When 50 gm of sample of activated charcoal was kept in a flask of 1 lit capacity at T k. The volume of gas adsorbed per gram of charcoal at 190 mm of Hg at same T k is ----------------ml

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