First slide

Hydrogen Peroxide

Question

When H₂O₂ is shaken with acidified solution of K₂Cr₂O₇ in the presence of ether, the etherial layer turns blue due to the formation of :

Moderate

A

${Cr}_{2} O_{3}$
B

${CrO}_{4}^{2 -}$
C

${Cr}_{2} {({SO}_{4})}_{3}$
D

CrO₅

Solution

$\underset{Orange}{K_{2} {Cr}_{2} O_{7}} + H_{2} {SO}_{4} + 4 H_{2} O_{2} \to_{Ether}^{Ice cold} K_{2} {SO}_{4} + 5 H_{2} O + \underset{Blue}{2 {CrO}_{5}}$

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