When I2 oxidizes S2O3-2 , the average oxidation number of Sulphur in the product formed is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

+2.5

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

2S2O3-2+I2→S4O6-2+2I-Oxidation state of S = +5,0,0,+5Average oxidation state =5+0+0+54=2.5

Watch 3-min video & get full concept clarity