Zero order reactions

Question

When initial concentration of the reactant is doubled, the half-life period of a zero order reaction

Easy

Solution

${\left({\mathrm{t}}_{1/2}\right)}_{\text{zero}}=\frac{[\mathrm{A}{]}_{0}}{2\mathrm{k}}$

As the half-life of a zero order reaction is directly proportional to initial concentration.

$\therefore $ If $\left[{\mathrm{A}}_{0}\right]$= doubled then, =${\mathrm{t}}_{1/2}$ doubled.

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