When KMnO4 acts as an oxidizing agent and ultimately forms MnO4-2, MnO2, Mn2O3, Mn+2, then the number of electrons transferred in each case respectively is
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a
4, 3, 1, 5
b
1, 5, 3, 7
c
1, 3, 4, 5
d
3, 5, 7, 1
answer is C.
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Detailed Solution
Number of e- transferred in each case = Change in oxidation state. Mn+7O4-→Mn+6O4-2 ; 1 e- is transfered MnO4-→Mn+4O2 ; 3 e- are transfered. MnO4-→Mn+32O3 ; 4 e- are transfered. MnO4-→Mn+2 ; 5 e- are transfered.