Q.

When KMnO4 acts as an oxidizing agent and ultimately forms MnO4-2, MnO2, Mn2O3,  Mn+2, then the number of electrons transferred in each case respectively is

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a

4, 3, 1, 5

b

1, 5, 3, 7

c

1, 3, 4, 5

d

3, 5, 7, 1

answer is C.

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Detailed Solution

Number of e- transferred in each case  = Change in oxidation state. Mn+7O4-→Mn+6O4-2 ;  1 e- is transfered MnO4-→Mn+4O2 ;    3 e- are transfered. MnO4-→Mn+32O3 ;  4 e-  are transfered. MnO4-→Mn+2 ;   5 e- are transfered.
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