Q.
When 22.4 litres of H2(g) is mixed with 11.2 litres of Cl2(g), each at S.T.P, the moles of HCl (g)formed is equal to
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya
answer is 1.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
1 mole ≡22.4 litres at S.T.P. nH2=22.422.4=1 mol,nCl2=11.222.4=0.5 molreaction is as H2(g) + Cl2(g) ⟶ 2HCl(g) Initial 1 mol0.5 mol 0 Final (1-0.5)=0.5 (0.5-0.5)=0 2×0.5=1Here, Cl2 is limiting reagent. So, 1 mole of HCl(g) is formed.
Watch 3-min video & get full concept clarity