Hydrogen Peroxide

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Question

When 20 ml of 2.5M H₂O₂ aqueous soultion is decomposed the S.T.P. volume of oxygen obtained is

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Solution

$\large {V_{{H_2}{O_2}}}\; = \;20ml$

$\large {M_{{H_2}{O_2}}}\; = \;2.5$

$\large M\; = \;n \times \frac{{1000}}{{V(in\;ml)}}$

$\large \eta = \;\frac{{M \times v[in\;ml]}}{{1000}}$

$\large \eta = \;\frac{{2.5 \times 20}}{{1000}}$

$\large \eta \; = \;0.05$

No.of moles of H₂O₂ (η)=0.05moles

$\large \mathop {2{H_2}{O_2}}\limits_{2\;moles} {\text{ }} \to {\text{ }}2{H_2}O + \mathop {{O_2}}\limits_{1\;moles}$

$\large \\2\;moles\;of\;{H_2}{O_2}\;solution\;\xrightarrow{{\;\;\Pr oduces}}\;1 \times 22400\;ml = \;22.4lit\;{O_2}$

0.05 moles of H₂O₂ solution → ?? ml of O₂

$\frac{0.05 \times 22400}{2} = \frac{5 \times 224}{2}$

= 5 x 112
=560 ml

$\therefore$
2ml of 2.5 H₂O₂ aqueous solution is on decomosition at STP produces 560 ml of O₂.

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Hydrogen Peroxide

Remember concepts with our Masterclasses.

When 20 ml of 2.5M H2O2 aqueous soultion is decomposed the S.T.P. volume of oxygen obtained is

No.of moles of H2O2 (η)=0.05moles 0.05 moles of H2O2 solution → ?? ml of O2 0.05×224002=5×2242= 5 x 112=560 ml 2ml of 2.5 H2O2 aqueous solution is on decomosition at STP produces 560 ml of O2.

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When 20 ml of 2.5M H₂O₂ aqueous soultion is decomposed the S.T.P. volume of oxygen obtained is