First slide

Hydrogen Peroxide

Question

When 20 ml of 2.5M H₂O₂ aqueous soultion is decomposed the S.T.P. volume of oxygen obtained is

Easy

Solution

$\large {V_{{H_2}{O_2}}}\; = \;20ml$

$\large {M_{{H_2}{O_2}}}\; = \;2.5$

$\large M\; = \;n \times \frac{{1000}}{{V(in\;ml)}}$

$\large \eta = \;\frac{{M \times v[in\;ml]}}{{1000}}$

$\large \eta = \;\frac{{2.5 \times 20}}{{1000}}$

$\large \eta \; = \;0.05$

No.of moles of H₂O₂ (η)=0.05moles

$\large \mathop {2{H_2}{O_2}}\limits_{2\;moles} {\text{ }} \to {\text{ }}2{H_2}O + \mathop {{O_2}}\limits_{1\;moles}$

$\large \\2\;moles\;of\;{H_2}{O_2}\;solution\;\xrightarrow{{\;\;\Pr oduces}}\;1 \times 22400\;ml = \;22.4lit\;{O_2}$

0.05 moles of H₂O₂ solution → ?? ml of O₂

$\frac{0.05 \times 22400}{2} = \frac{5 \times 224}{2}$

= 5 x 112
=560 ml

$\therefore$
2ml of 2.5 H₂O₂ aqueous solution is on decomosition at STP produces 560 ml of O₂.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App