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Faraday's Laws

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By Expert Faculty of Sri Chaitanya
Question

When 0.1 mol  MnO42-  is  oxidised, the quantity of electricity required to completely oxidise  MnO42- to  MnO41-  is

Easy
Solution

The oxidation reaction is

Mn+6O42-0.1 mol Mn+7O4- +e-0.1 mol

Q=0.1×F=0.1×96500C=9650C

 


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