When 1 mol of a monatonic ideal gas at T K undergoes adiabatic change under a constant external pressure of 1 atm, changes volume from 1L to 2 L. The final temperature (in K) would be
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a
T223
b
T+23×0.0821
c
T
d
T-23×0.0821
answer is D.
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Detailed Solution
ΔE=W;Q=0W=-PextΔV=-1.L.atmΔE=nCvΔT Cv=Rγ-1;γ=53; for mono atomic gas Cv=R53-1=3R2;n=1ΔE=1×3R2×T2-T1=-13RT22-3RT2=-13RT22=3RT2-1 T2=T-1×23×0.0821
When 1 mol of a monatonic ideal gas at T K undergoes adiabatic change under a constant external pressure of 1 atm, changes volume from 1L to 2 L. The final temperature (in K) would be