Q.

When 0.1 mole of MnO42- is oxidised, the quantity of electricity required to completely oxidise MnO42- to MnO4-

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a

96500 C

b

2 x 96500 C

c

9650 C

d

96.50 C

answer is C.

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Detailed Solution

MnO42-+6⇌MnO4-(+7)As per the equation, for 1 mole of MnO42-,1 F of electricity is required. Thus, for 0.1 mole of MnO42- to MnO4-F of electricity is required.Since; 1 F = 96500 C∴    0.1 F=0.1 ×96500 C=9650 CHence, 9650 C of electricity is required to completely oxidise MnO42- to MnO4-.
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When 0.1 mole of MnO42- is oxidised, the quantity of electricity required to completely oxidise MnO42- to MnO4-