When 0.1 mole of MnO42- is oxidised, the quantity of electricity required to completely oxidise MnO42- to MnO4-
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a
96500 C
b
2 x 96500 C
c
9650 C
d
96.50 C
answer is C.
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Detailed Solution
MnO42-+6⇌MnO4-(+7)As per the equation, for 1 mole of MnO42-,1 F of electricity is required. Thus, for 0.1 mole of MnO42- to MnO4-F of electricity is required.Since; 1 F = 96500 C∴ 0.1 F=0.1 ×96500 C=9650 CHence, 9650 C of electricity is required to completely oxidise MnO42- to MnO4-.