When 1 mole of N2 and 1 mole of H2 is enclosed in a 5L vessel and the reaction is allowed to attain equilibrium. It is found that at equilibrium there is x mole of H2 . The number of moles of NH3 formed would be

N2+3H2⇌2NH3            1           1                 0               α         3α              2α_    (1−α)     (1−3α)     2α           Given    1−3α=x                        3α=1−x                          α=1−x3      ∴ Number of molesNH3=2α=2(1−x3)