First slide

Theory of dilute solutions

Question

When 0.01 moles of solid HgI₂ is completely dissolved in a solution containing 0.02moles of KI in 100g of H₂O, the depression in the freezing point of the solution is
(K_f for H₂O is 1.86 K.Kg mol^-1)

Moderate

A

-0.558K
B

0.558K
C

-0.744K
D

0.744K

Solution

$2 KI (a q) + {HgI}_{2} (s) \to K_{2} [{HgI}_{4}] (aq) \to 2 K^{+} + {[{HgI}_{4}]}^{2 -}$
$0.02 0.01 0$
$After reaction 0 0 0.01 0.02 0.01$
$Molality of particles of solute = \frac{0.03}{100} \times 1000$
$Δ T_{f} = 1.86 \times 0.3$
= 0.558 K

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