Q.

When a solution containing w g of urea in 1 kg of water is cooled to −0.372oC, 200 g of ice is separated. If Kf for water is 1.86 K kg mol-1, w is

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4.8 g

12.0 g

9.6 g

6.0 g

answer is C.

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Detailed Solution

Mass of water present in the solution at the freezing pt. =1000−200=800 gΔTf=0.372=1000×kfw60×800=1000×1.86×w60×800 w=9.6 g

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