When sulphur (in the form of S8) is heated at temperature T at equilibrium, the pressure of S8 falls by 30% from 1.0atm, because S8 (g) is partially converted into S2 (g). Find the value of K p for this reaction.

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2.96

6.14

204.8

None of these

answer is C.

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Detailed Solution

S8(g)⇌4S2(g)Initially : 1 0At equi. 1−x 4x x leads falls by 30%x=0.3Kp=PS2( g)4PS8( g)=(4×0.3)40.70=2.96

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