When xenon hexafluoride is completely hydrolysed a xenon compound ‘A’ is formed. The number of -bond, -bonds and lone pairs present on Xe in ‘A’ respectively are
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a
4, 4,1
b
3, 3, 1
c
4.1,1
d
4,2,0
answer is B.
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Detailed Solution
xenon hexafluoride on complete hydrolysis gives xenontrioxide. XeF6 + 3H2O→XeO3 + 6HFThe number of σ-bonds=3, π -bonds=3 and lone pairs=1