Q.
Unlock the Full Solution and Master the Concept
Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya
a
The number of first neighbours of S2− is 4
b
The maximum distance between Zn2+ is a32, where ' a ' = edge length of unit cell
c
If all tetrahedral voids are occupied by Zn2+ then C.N. of S2− is 8.
d
If all tetrahedral voids are occupied by Zn2+ then C.N. change from 4:4 to 8:8.
answer is 1,2,3.
(Detailed Solution Below)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Choose your Grade and Exam
