Q.
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a
The number of first neighbours of S2− is 4
b
The maximum distance between Zn2+ is a32, where ' a ' = edge length of unit cell
c
If all tetrahedral voids are occupied by Zn2+ then C.N. of S2− is 8.
d
If all tetrahedral voids are occupied by Zn2+ then C.N. change from 4:4 to 8:8.
answer is A.
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