First slide

Diborane

Question

Which cannot be prepared by B₂H₆ ?

Easy

A

NaBH₄
B

H₃BO₃
C

B₂(CH₃)₆
D

2(CH₃)₃N.B₂H₆

Solution

Bridging hydrogen atoms cannot involve in methylation,therefore no formation of $B_{2} {({CH}_{3})}_{6}$

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