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In which case is number of molecules of water maximum?

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Detailed Solution

(a) Mass of water =V×d=18×1=18 g Molecules of water =mole×NA=1818NA=NA (b) Molecules of water = mole ×NA=0.1818NA=10-2NA (c) Moles of water =0.0022422.4=10-4 Molecules of water = mole ×NA=10-4 NA (d) Molecules of water = mole ×NA=10-3NA
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In which case is number of molecules of water maximum?