Which is the correct order of ionic size (At. No. : Ce = 58, Sn = 50, Yb = 70 and Lu = 71) ?
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a
Ce > Sn > Yb > Lu
b
Sn > Ce > Lu > Yb
c
Lu > Yb > Sn > Ce
d
Sn > Yb > Ce > Lu
answer is B.
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Detailed Solution
Correct order of ionic size is Sn > Ce > Lu > Yb.Sn belongs to IVA group, which is larger than Lanthanides.Among the lanthanides size decreases But Lu>Yb due to completely filled configuration of Lu.