Which is correct statement about the electrolysis of aqueous solution of CuSO4 with copper cathode and Pt anode?

Anode 2H2O(l)⟶4H+(aq.)+O2(g)+4e− Cathode Cu+2+2e-⇌Cu(s)As number of OH- ions decreases hence H+ increases so pH of solution decreases, Number of Cu2+ ions decreases so blue colour intensity decreases during electrolysis.