Which of the following are wrong ?

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SH6 and BiCl5 do not exist

There are two pπ−dπ bonds in SO3.

SeF4 and CH4 are tetrahedral ion.

I3Θ is a linear molecule with sp3d hybridisation

answer is C.

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Detailed Solution

(a) SH6 and BiCl5 do not exist. In SH6, EN of H-atom is not sufficient to excite e− s from 3p orbital to 3d orbitals from S-atom. In BiCl5, Bi3+ is more stable than Bi5+ due to inert pair effect.(b) pπ−dπ bond=1, pπ−dπ bond=2(c) Wrong. Hybridization of : SeF4 ⇒12 6+4=5=sp3dGeometry = due to one lone-pair of e− s its shape is see-saw.Hybridization of CH4⇒ sp3 and tetrahedral.(d) Correct. Hybridization of I3Θ H2Θ ⇒ 12 7+2+1=5 =sp3dDue to three lone-pair of e−s, it is linear.

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