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Q.

Which of the following are wrong ?

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a

SH6 and   BiCl5 do not exist

b

There are two pπ−dπ  bonds  in  SO3.

c

SeF4  and  CH4 are tetrahedral ion.

d

I3Θ is a linear molecule with sp3d hybridisation

answer is C.

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Detailed Solution

(a) SH6  and  BiCl5 do not exist. In SH6, EN of H-atom is not sufficient to excite e−  s from 3p orbital to 3d orbitals from S-atom. In BiCl5,  Bi3+ is more stable than Bi5+ due to inert pair effect.(b) pπ−dπ  bond=1,  pπ−dπ  bond=2(c) Wrong. Hybridization of : SeF4 ⇒12 6+4=5=sp3dGeometry = due to one lone-pair of e−  s its shape is see-saw.Hybridization of CH4⇒ sp3 and tetrahedral.(d) Correct. Hybridization of I3Θ  H2Θ ⇒  12  7+2+1=5  =sp3dDue to three lone-pair of e−s, it is linear.
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