Which of the following is aromatic carbocation?

[Step 1]:In option (1), two carbons are SP3 and non-planar.Non conjugated and not obeys Huckel’s rule[Step 2]:In option (2) all three carbons are SP2 planar cyclic, conjugated and contains 2πe- i.e,  obeys Huckel’s rule. Therefore it is an aromatic compound[Step 3]:In option (3) one carbon is SP3 and non-planar[Step 4]:In option (4) , number of πe- are 4 i.e, not obeys Huckel’s rule.