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Which of the following is aromatic carbocation?
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b
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Correct option is B
[Step 1]:In option (1), two carbons are SP3 and non-planar.Non conjugated and not obeys Huckel’s rule[Step 2]:In option (2) all three carbons are SP2 planar cyclic, conjugated and contains 2πe- i.e, obeys Huckel’s rule. Therefore it is an aromatic compound[Step 3]:In option (3) one carbon is SP3 and non-planar[Step 4]:In option (4) , number of πe- are 4 i.e, not obeys Huckel’s rule.Talk to our academic expert!
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