First slide

Nernst Equation

Question

In which of the following cells $E_{cell} = E_{cell}^{\circ}$ ?

Easy

A

$Cu (s) |{Cu}^{2 +} (0 .01 M)| |{Ag}^{+} (0 .1 M)| Ag (s)$
B

$Pt (H_{2}) | pH = 1 | |{Zn}^{2 +} (0 .01 M)| Zn (s)$
C

$Pt (H_{2}) | pH = 1 | |{Zn}^{2 +} (1 M)| Zn (s)$
D

$Pt (H_{2}) |H^{+} = 0 .01 M| |{Zn}^{2 +} (0 .01 M)| Zn (s)$

Solution

From Nernst equation, $E_{cell} = E_{cell}^{\circ} - \frac{0 .0591}{nF} \log Q .$
If $Q = 1, \log Q = 0 so, E_{cell} = E_{cell}^{\circ}$
This condition is found in (a) and (b).

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