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Q.

In which of the following entropy change is +Ve

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a

I2(g)→I2(s)

b

Cgraphite→CDiamond

c

AgNO3(s)→AgNO3(aq)

d

N2(g)+3H2(g)→2NH3(g)

answer is C.

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Detailed Solution

i) If gas converted in to solid entropy decreases ΔS=−veii) Cgraphite→CDiamond Diamond has more regular geometry          than graphite so entropy decreases∴ΔS=−veiii) AgNO3(s)→AgNO3(aq)due to hydration and ionization randomness  increases ΔS=+veiv) No. of moles of gaseous products decreases so does entropy  ΔS=−ve
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