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a
I2(g)→I2(s)
b
Cgraphite→CDiamond
c
AgNO3(s)→AgNO3(aq)
d
N2(g)+3H2(g)→2NH3(g)
answer is C.
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Detailed Solution
i) If gas converted in to solid entropy decreases ΔS=−veii) Cgraphite→CDiamond Diamond has more regular geometry than graphite so entropy decreases∴ΔS=−veiii) AgNO3(s)→AgNO3(aq)due to hydration and ionization randomness increases ΔS=+veiv) No. of moles of gaseous products decreases so does entropy ΔS=−ve