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An Intiative by Sri Chaitanya
a
E=0.05922log aPb2+RHS aPb2+LHS
b
E=0.05922log aPb2+LHS aPb2+RHS
c
E=0.05922logKspPbI21/3
d
E=0.05922logKspPbI2KspPbSO4
answer is A.
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