Q.

Which of the following expressions represent the EMF of the above cell at 25°C?

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya

a

E=0.05922log⁡ aPb2+RHS aPb2+LHS

b

E=0.05922log⁡ aPb2+LHS aPb2+RHS

c

E=0.05922log⁡KspPbI21/3

d

E=0.05922log⁡KspPbI2KspPbSO4

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Pb(s)(I)PbSO4  PbI2(II)Pb(s) Pb⟶Pb12++2e−    (oxidation)PbII2++2e−⟶Pb    (Reduction) Net cell reaction:  Pb𝕀2+⟶Pb12+Ece𝕀𝕀=Ecell′−0.0592nlog⁡Pb2+IPb2+II [Nernst's equation] Ecell°=0, ∴ Ecell=0.0592nlog⁡Pb2+IIPb2+I
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

+91
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
whats app icon