Q.

Which of the following expressions represent the EMF of the above cell at 25°C?

Moderate

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By Expert Faculty of Sri Chaitanya

E=0.05922log⁡ aPb2+RHS aPb2+LHS

E=0.05922log⁡ aPb2+LHS aPb2+RHS

E=0.05922log⁡KspPbI21/3

E=0.05922log⁡KspPbI2KspPbSO4

answer is 1.

(Detailed Solution Below)

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Detailed Solution

Pb(s)(I)PbSO4 PbI2(II)Pb(s) Pb⟶Pb12++2e− (oxidation)PbII2++2e−⟶Pb (Reduction) Net cell reaction: Pb𝕀2+⟶Pb12+Ece𝕀𝕀=Ecell′−0.0592nlog⁡Pb2+IPb2+II [Nernst's equation] Ecell°=0, ∴ Ecell=0.0592nlog⁡Pb2+IIPb2+I

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