Questions

Which of the following expressions represent the EMF of the above cell at 25°C?

Unlock the full solution & master the concept.

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept

By Expert Faculty of Sri Chaitanya

E=0.05922log⁡ aPb2+RHS aPb2+LHS

E=0.05922log⁡ aPb2+LHS aPb2+RHS

E=0.05922log⁡KspPbI21/3

E=0.05922log⁡KspPbI2KspPbSO4

NEW

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is A

Pb(s)(I)PbSO4 PbI2(II)Pb(s) Pb⟶Pb12++2e− (oxidation)PbII2++2e−⟶Pb (Reduction) Net cell reaction: Pb𝕀2+⟶Pb12+Ece𝕀𝕀=Ecell′−0.0592nlog⁡Pb2+IPb2+II [Nernst's equation] Ecell°=0, ∴ Ecell=0.0592nlog⁡Pb2+IIPb2+I

Similar Questions

The conductivity of a saturated solution of ${Ag}_{2} C_{2} O_{4}$ is $4 \times 10^{- 5} S c m^{- 1}$ at 25°C. Conductivity of water is $6 \times 10^{- 8} S c m^{- 1}$ . What is the approximate molar conductivity of $C_{2} O_{4}^{2 -}$ ion at infinite dilution, given molar conductivity of Ag+ ions at infinite dilution is $62 S c m^{2} / m o l$ and $K_{sp} ({Ag}_{2} C_{2} O_{4}) = 3 .2 \times 10^{- 11}$