Q.
Which of the following graphs are correct for a first order reaction?
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a
b
c
d
answer is A.
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Detailed Solution
For the first order reaction,k=2.303tlog [R]0[R]⇒kt2.303=log [R]0[R] log RoR=k2.303x t+0 ↑ ↑ ↑ ↑ y = m x +c Correct plot of log RoR can be represented by (d)where, slope = k2.303The time taken for any fraction of the reaction to complete is independent of the initial concentration.Let, us consider it for half of the reaction to complete. t=2303klog aa−xFor half-life (t)=t1/2 and x=a2 t1/2=2.303klog aa−a2 t1/2=2.303klog 2 Half-life time t1/2=0.693kt12is independent of initial concentration. Hence, correct plot of t12 and Rocan be represented by option (a).
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