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a
NaCl
b
CuCl
c
CuCl2
d
CsCl
answer is C.
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Detailed Solution
According to Fajan’s rule, as the size of cation decreases, its polarising power increases. Hence, Cu2+ polarise Cl- ions more than Cu+. Therefore, CuCl2 has more covalent character and hence, its boiling point is less.